diff options
-rw-r--r-- | markdown/blockprocessors.py | 10 | ||||
-rw-r--r-- | tests/misc/some-test.html | 4 |
2 files changed, 6 insertions, 8 deletions
diff --git a/markdown/blockprocessors.py b/markdown/blockprocessors.py index 13bc477..64b9e09 100644 --- a/markdown/blockprocessors.py +++ b/markdown/blockprocessors.py @@ -300,11 +300,11 @@ class OListProcessor(BlockProcessor): CHILD_RE = re.compile(r'^[ ]{0,3}((\d+\.)|[*+-])[ ]+(.*)') # Detect indented (nested) items of either type INDENT_RE = re.compile(r'^[ ]{4,7}((\d+\.)|[*+-])[ ]+.*') - # The integer with which the lists starts (None means start with 0) + # The integer (python string) with which the lists starts (default=1) # Eg: If list is intialized as) # 3. Item # The ol tag will get starts="3" attribute - STARTSWITH = None + STARTSWITH = '1' def test(self, parent, block): return bool(self.RE.match(block)) @@ -345,7 +345,7 @@ class OListProcessor(BlockProcessor): # This is a new list so create parent with appropriate tag. lst = util.etree.SubElement(parent, self.TAG) # Check if a custom start integer is set - if self.STARTSWITH: + if self.STARTSWITH !='1': lst.attrib['start'] = self.STARTSWITH self.parser.state.set('list') @@ -372,9 +372,7 @@ class OListProcessor(BlockProcessor): if not items and self.TAG=='ol': # Detect the integer value of first list item INTEGER_RE = re.compile('(\d+)') - start_integer = INTEGER_RE.match(m.group(1)).group() - if start_integer!='1': - self.STARTSWITH = start_integer + self.STARTSWITH = INTEGER_RE.match(m.group(1)).group() # Append to the list items.append(m.group(3)) elif self.INDENT_RE.match(line): diff --git a/tests/misc/some-test.html b/tests/misc/some-test.html index b78683f..92e7262 100644 --- a/tests/misc/some-test.html +++ b/tests/misc/some-test.html @@ -51,7 +51,7 @@ ok with a bunch of items</li> <li> <p>Mostly fruits</p> -<ol> +<ol start="3"> <li>Apple</li> <li>Pare</li> </ol> @@ -65,4 +65,4 @@ Another code example * Lists and similar stuff > Should be ignored -</code></pre>
\ No newline at end of file +</code></pre> |